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tradingcube

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About tradingcube

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    Steve Pickup
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  1. Using Arrays with no duplicated values

    Hello, i'm new houdini, new to vex and not done any programming for a long time (most of the forum sighs) Coming from a 3DS Max background I’m absolutely loving Houdini, and can really see the power VEX can have so trying to focus a good chunk of my learning time to get comfortable with it right from the start. I've been building a very simple point infection model to get familiar with the various bits and pieces. As part of this I’ve been storing point numbers to an array, using this in a solver and each frame more pt number get added. The only way i could see to do this was to take two arrays, combine them and then deduplicate, but this seemed a bit long winded and not very efficient. Searching around Stack overflow I noticed that in Javascript there was a find function and also this exists in VEX so instead have now used that to search the array and add any unique points on-the-fly. I guess my question is whether this is actually the best way to do this? It's little frustrating that find() isn’t listed on the https://www.sidefx.com/docs/houdini/vex/arrays.html page as I’d have probably tried it sooner. Which is why I’m wondering if there is a reason it's not on there? Sorry bit long winded and hope this makes sense These are the two options ive used: using Find() and only writing if not already in the array i[]@pointsArray1 = {0,2,7,8,10}; i[]@pointsArray2 = {0,3,5,7,8,11,15,16,10}; for (int i=0; i<len(i[]@pointsArray2);i++){ if (!(find(i[]@pointsArray1, i[]@pointsArray2[i])>=0)) { push(i[]@pointsArray1,i[]@pointsArray2[i]); } } De duplicating the array post i[]@pointsArray1 = {0,2,7,8,10}; i[]@pointsArray2 = {0,3,5,7,8,11,15,16,10}; i[]@newArray; foreach (int num; i[]@pointsArray1){ for(int i = 0; i<len(i[]@pointsArray2);i++){ if(num == i[]@pointsArray2[i]){ push(i[]@newArray,i[]@pointsArray2[i]); } } } push(i[]@pointsArray1,i[]@pointsArray2); for(int i = 0; i<len(i[]@newArray);i++){ removevalue(i[]@pointsArray1,i[]@newArray[i]); } thanks
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