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Matrix : practical reading /printing

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Dear all,


Sorry if my question looks naive, as you're all surely usual with this : matrix reading /printing.

But i'd like to "printf" it element by element. Usually, generally a matrix looks like : matrix M[r][c] -> then your iter through. eg : print(M[1][1]+"\n");

But here in Hou it is : matrix M

Yes printf() prints the thing but the whole thing. Then, how to read elements one by one separatly, please? i humbly dunno.

Am usual with this practice in other languages because Matrices could be used as a fantastic "Chest" to store values, compiling vectors pack, and on and on...


So any advices to this practical question are welcome.


Thank you a lot.




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For some reason M[1][1] is not working in VEX, but you can always use getcomp(M, 1, 1).

for (int row = 0; row < 4; row++)
    string out = "";
    for (int col = 0; col < 4; col++)
        float value = getcomp(4@test, row, col);
        out += sprintf("%g  ", value);
    printf(out + "\n");

Matrices in Houdini are not m×n arrays, but 4-, 9- and 16-float "vectors". They rarely used as storage, as there is one-dimension arrays available for this purpose. Python is generally used for more sophisticated arrays manipulation. NumPy available by default.

import numpy

node = hou.pwd()
geo = node.geometry()

mat = geo.floatListAttribValue('test');
val = numpy.array(mat).reshape((4, 4))



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Dear F1,

Thank you for explanations, because i've found myself in front of a locked door which finally was more like an illusion as you're explaining the classic "for" iteration is working. Thus we can say even if the academic notation : M[][] doesn't work, its functionality is implicitly embeded inside DOGMATIC 2x2 3x3 or 4x4...so...perfect.


i deduce then the reverse getcomp() is setcomp().

I can now, sort, store , arrage datas inside. GR8 !

Thank you twice F1, and enjoy the week end.


alr + + +


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