Adam Ferestad Posted June 21, 2011 Share Posted June 21, 2011 I am trying to get the angle of a right triangle, and for that I need tan^-1(b/a), but I can't seem to find the inverse trig functions in the expression help? Is there another way to do this in an expression alone or will i have to use a special node to calculate the angle? I can't for the life of me figure out how to do it without that operator. Quote Link to comment Share on other sites More sharing options...
anim Posted June 21, 2011 Share Posted June 21, 2011 they are called: asin() acos() atan() and for special cases atan2() Quote Link to comment Share on other sites More sharing options...
Adam Ferestad Posted June 21, 2011 Author Share Posted June 21, 2011 OK, I didn't realize that the arc trig functions were the same as the inverse. Thanks. Quote Link to comment Share on other sites More sharing options...
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