for loop in one line

[pelos]

i am trying to put a code into a button that will print the values of some parameters, i was able to make a list with

t = [x for x in hou.pwd().parms() if x.name().startswith("blend")];

then i can print the list of the parameters that  i want with 

print t;

 

 

but if i want to do something to each one is when starts to break:

t = [x for x in hou.pwd().parms() if x.name().startswith("blend")]; print t; for i in t:   print i.eval();

 

 

 

the funny thing is if i print all directly with out doing the filter list does work =(

for i in hou.pwd().parms():   print i.eval();

 

 

any cool tip that might work?

 

thanks.

[graham]

You should be able to do something like this:

for i in (x for x in hou.pwd().parms() if x.name().startswith("blend")): print i.eval()

It removes one of the loops, but you also have to do it as a generator expression, rather than a list comprehension, thus the () instead of the [].

[pelos]

thanks graham, cool trick =).

 

do you know why for i in t" doesnt work in houdini?  we tought that we could store the list in a variable t, and then use another loop.

[graham]

Unfortunately I'm not too sure about the intricacies about Python and single line statements.  It's also no a Houdini specific thing.  If you take the giant line from up there that doesn't work in Houdini, it doesn't work in Python either.