ndeboar Posted January 11, 2017 Share Posted January 11, 2017 (edited) Hey, See attached. I found this example in another thread (totally forgot which one, sorry!). I have some questions about this setup: - This is the first time i have seen targetV used rather than just v. What is the advantages of targetV over v? - How would you go about "deflating" the balloon? I tried just negating the targetV, with little success. Cheers, Nick inflate_01_a_012_fix2.hiplc Edited January 11, 2017 by ndeboar Quote Link to comment Share on other sites More sharing options...
merlino Posted January 11, 2017 Share Posted January 11, 2017 Consider that if you set a "v" you are forcing a velocity for a point, exactly that velocity. "targetv" works like a goal, you're not setting a hard value for the velocity, just a goal and the solver try to reach that velocity. Something like this can help with the "deflating"? inflate_01_a_012_fix2_mem.hiplc Quote Link to comment Share on other sites More sharing options...
ndeboar Posted January 18, 2017 Author Share Posted January 18, 2017 Hey, Sorry for the late reply. TargetV: Makes sense Deflate: The old position vector, that should do the trick Nick Quote Link to comment Share on other sites More sharing options...
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