CinnamonMetal Posted October 21, 2018 Share Posted October 21, 2018 I want to get the prim_normal() based on the value of four string channels. The four string channels return four different values string Sx = chs("../transform1/sx"); string Sy = chs("../transform1/sy"); string Tz = chs("../transform1/tz"); string SherY = chs("../transform1/shear2"); With those values, each unique. I don't know how to get the prim_normal() to read those string values independently of each other, but still return the parametric location u, v; as does prim_normal() ? Quote Link to comment Share on other sites More sharing options...
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