Drughi Posted January 19, 2018 Share Posted January 19, 2018 Hello! If you take two wrangles. The first one is: v@oldpos = @P; the second one is: @P = @oldpos; Shouldn't the result be just the same? I'm ending up having just some points clustered on the y axis. strange.hiplc Quote Link to comment Share on other sites More sharing options...
Gorrod Posted January 19, 2018 Share Posted January 19, 2018 in the second wrangle, write @P = v@oldpos; You have to tell it that oldpos is a vector and not a float attribute. Quote Link to comment Share on other sites More sharing options...
AntoineSfx Posted January 19, 2018 Share Posted January 19, 2018 Second wrangle should be: @P = v@oldpos; Otherwise, it's doing this really: @P=v@oldpos[0]; Untyped @oldpos is cast into its first component. Quote Link to comment Share on other sites More sharing options...
Drughi Posted January 19, 2018 Author Share Posted January 19, 2018 Thanks a lot! Quote Link to comment Share on other sites More sharing options...
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