if in list (vex)

[gerardocastellanos]

Hello

how can I query if an element is in a list or not?

in python is "  if element in list: "

 

thanks you.

[anim]

You can use find() function, if the resulting index is negative, element is not in the array

[gerardocastellanos]

thans you!

[gerardocastellanos]

I stored different index (integer number) in my primitives, and I want to create an array detail attribute with all my different index.

sometimes my geometry could has 4 different index, for example (3,6,7,2), but in another case it could has 6 or 8 different numbers.

my idea is store in a detail attribute that list of numbers (index)

 

I create an primitive wrangle with this:

 

int indexList[] = detailattrib(0, "indexList",0,1);

if (!find(indexList, @index)){
push(indexList, (int)@index);

setdetailattrib(0, "indexList", indexList);
}

 

but it does not work as I expect.

what I am doing wrong?

 

thanks

Edited October 13, 2019 by gerardocastellanos

[anim]

as I mentioned if returned index by find() is negative it's not found

your test simply tests if it's 0, which is actually still a valid index

 

so you want to do :

if (find(indexList, @index) < 0)

Edited October 13, 2019 by anim