davidyannick Posted October 5, 2020 Share Posted October 5, 2020 Last year I.'ve modelled this character in Houdini, now I've switched to full houdini workflow Is there a way to model this character in a procedural way, I've tried with vdb and scale attr but the result is not good, have you any hint, idea on how I can make this "character generator " ? THanks Quote Link to comment Share on other sites More sharing options...
Librarian Posted October 6, 2020 Share Posted October 6, 2020 Try ISO Surface.. just make different channels in parameters and model with 50 division. Penguin. (($Z-1.8)^2+($Y+0.3)^2+($X+0.3)^2-0.01)* (($Z-1.8)^2+($Y+0.3)^2+($X-0.3)^2-0.01)* ((-($Y-1.5)-2.5-2.8*($X+0.5)^2)^2 + 0.1*$X^2 +0.1*($Y-1.5)^2 +8*($Z+2)^2 -0.8)* ((-($Y-1.5)-2.5-2.8*($X-0.5)^2)^2 + 0.1*$X^2 +0.1*($Y-1.5)^2 +8*($Z+2)^2 -0.8)* (5*($Z-1.5)^2 +4*$X^2 -($Y+1.2)^3*(1-($Y+1.2))-0.01)* (((0.3*($Z+0.5)^2+$Y^2+$X^2-1)* (0.3*($Z-1.3)^2+$Y^2+$X^2-0.3)* (20*(($Z-0.5)*cos( 1.3)-($X+0.5)*sin( 1.3))^2 +0.7*(($Z-0.5)*sin( 1.3)+($X+0.5)*cos( 1.3)+1.4)^2 +2*$Y^2-1)* (20*(($Z-0.5)*cos(-1.3)-($X-0.5)*sin(-1.3))^2 +0.7*(($Z-0.5)*sin(-1.3)+($X-0.5)*cos(-1.3)-1.4)^2 +2*$Y^2-1))-0.5) Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.