Jump to content

Organic modeling


davidyannick

Recommended Posts

Last year I.'ve modelled this character in Houdini, now I've switched to full houdini workflow

Is there a way to model this character in a procedural way, I've tried with vdb and scale attr but the result is not good, have you any hint, idea on how I can make this "character generator " ?

THanks

120027812_3474325892624865_5815158957001225293_n.png

Capture d’écran 2020-10-05 à 22.40.17.png

Link to comment
Share on other sites

Try ISO Surface.. just make different channels in parameters and model with 50 division.
Penguin.
 

(($Z-1.8)^2+($Y+0.3)^2+($X+0.3)^2-0.01)* (($Z-1.8)^2+($Y+0.3)^2+($X-0.3)^2-0.01)* ((-($Y-1.5)-2.5-2.8*($X+0.5)^2)^2 + 0.1*$X^2 +0.1*($Y-1.5)^2 +8*($Z+2)^2 -0.8)* ((-($Y-1.5)-2.5-2.8*($X-0.5)^2)^2 + 0.1*$X^2 +0.1*($Y-1.5)^2 +8*($Z+2)^2 -0.8)* (5*($Z-1.5)^2 +4*$X^2 -($Y+1.2)^3*(1-($Y+1.2))-0.01)* (((0.3*($Z+0.5)^2+$Y^2+$X^2-1)* (0.3*($Z-1.3)^2+$Y^2+$X^2-0.3)* (20*(($Z-0.5)*cos( 1.3)-($X+0.5)*sin( 1.3))^2 +0.7*(($Z-0.5)*sin( 1.3)+($X+0.5)*cos( 1.3)+1.4)^2 +2*$Y^2-1)* (20*(($Z-0.5)*cos(-1.3)-($X-0.5)*sin(-1.3))^2 +0.7*(($Z-0.5)*sin(-1.3)+($X-0.5)*cos(-1.3)-1.4)^2 +2*$Y^2-1))-0.5)

 

p.jpg

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...