iterate over certain points

[amin.khormaei]

I have this code below:

i[]@TP = neighbours(0,0);
foreach(int i ; @TP)
{
    @P.y = 1;
}

how can I tell Houdini to just move the points insideTP array?

foreach move all the points.

[animatrix]

Hi,

You can do it using a detail wrangle:

int pts [ ] = array ( 1, 3, 4 );
foreach ( int pt; pts )
    setpointattrib ( 0, "P", pt, 1 );

 

[amin.khormaei]

your code doesn't work

[fsimerey]

int pts [ ] = array ( 1, 3, 4 );
foreach ( int pt; pts ) {
      vector _P = {0,1,0}; // Create a vector
      setpointattrib ( 0, "P", pt, _P ); // Here all points would get the same position : _P -> (0,1,0)
    }

{} are missing, and attrib P is a vector, so you must put a vector and not a single integer.

In your case, if you want only change P.y on those points:

int pts [ ] = array ( 1, 3, 4 );
foreach ( int pt; pts ) {
      vector _P = point(0, "P", pt); // Get P attribute of point pt
      _P.y = 1.0;
      setpointattrib ( 0, "P", pt, _P );
    }

 

Edited September 15, 2020 by fsimerey

[vicvvsh]

3 hours ago, amin.khormaei said:

I have this code below:

i[]@TP = neighbours(0,0);
foreach(int i ; @TP)
{
    @P.y = 1;
}

how can I tell Houdini to just move the points insideTP array?

foreach move all the points.

Try this:

i[]@TP = neighbours(0,0);
foreach(int i ; @TP)
{
    if(i == @ptnum) @P.y = 1;
}

 

[animatrix]

3 hours ago, amin.khormaei said:

your code doesn't work

I tried it before posting, it works fine. Can you post what error are you seeing?

3 hours ago, fsimerey said:

int pts [ ] = array ( 1, 3, 4 );
foreach ( int pt; pts ) {
      vector _P = {0,1,0}; // Create a vector
      setpointattrib ( 0, "P", pt, _P ); // Here all points would get the same position : _P -> (0,1,0)
    }

{} are missing, and attrib P is a vector, so you must put a vector and not a single integer.

In your case, if you want only change P.y on those points:

int pts [ ] = array ( 1, 3, 4 );
foreach ( int pt; pts ) {
      vector _P = point(0, "P", pt); // Get P attribute of point pt
      _P.y = 1.0;
      setpointattrib ( 0, "P", pt, _P );
    }

 

1. {} is not needed in my code. Look here for similar C style syntax rules: http://www.cplusplus.com/forum/beginner/180452

2. You don't need to provide a vector type. VEX will automatically cast 0 into a vector.

[fsimerey]

4 hours ago, amin.khormaei said:

I have this code below:

i[]@TP = neighbours(0,0);
foreach(int i ; @TP)
{
    @P.y = 1;
}

how can I tell Houdini to just move the points insideTP array?

foreach move all the points.

 

10 minutes ago, animatrix said:

2. You don't need to provide a vector type. VEX will automatically cast 0 into a vector.

In the case of Amin, he seems want to move in Y axis. In your example the 1 give a vector (1,0,0), so moving along X axis AND ALL points are at the same position (1,0,0)...

Good to know for C style syntax

Edited September 15, 2020 by fsimerey

[animatrix]

13 minutes ago, fsimerey said:

 

In the case of Amin, he seems want to move in Y axis. In your example the 1 give a vector (1,0,0), so moving along X axis AND ALL points are at the same position (1,0,0)...

Good to know for C style syntax

No, 1 will become (1,1,1).

I just posted an example. He should be able to adapt it to his needs.

[fsimerey]

14 minutes ago, animatrix said:

No, 1 will become (1,1,1).

It's not correct. See attached file.

vector(1) give a vector of (1,1,1)

Edited September 15, 2020 by fsimerey

[amin.khormaei]

thank you for all answers. the simplest way was:

i[]@pts = neighbours(0,0);
foreach(int i ; @pts)
{
    if(i == @ptnum)
    {
        @P.y = 1;
    }
}

 

[anim]

3 hours ago, amin.khormaei said:

thank you for all answers. the simplest way was:

i[]@pts = neighbours(0,0);
foreach(int i ; @pts)
{
    if(i == @ptnum)
    {
        @P.y = 1;
    }
}

 

if your array is not varying per point (at least from your example) and you still want to use Point wrangle instead of detail you can simplify your code further to 

int pts[] = neighbours(0,0);
if(find(pts, @ptnum) >= 0) {
        @P.y = 1;
}

or @P.y += 1; if you want to offset them instead of hardcode to 1